Make binary info loading lazy
This commit is contained in:
@@ -155,9 +155,9 @@ namespace OpenRA.Editor
|
||||
var key = Map.Actors.FirstOrDefault(a => a.Value.Location() == BrushLocation);
|
||||
if (key.Key != null) Map.Actors.Remove(key.Key);
|
||||
|
||||
if (Map.MapResources[BrushLocation.X, BrushLocation.Y].type != 0)
|
||||
if (Map.MapResources.Value[BrushLocation.X, BrushLocation.Y].type != 0)
|
||||
{
|
||||
Map.MapResources[BrushLocation.X, BrushLocation.Y] = new TileReference<byte, byte>();
|
||||
Map.MapResources.Value[BrushLocation.X, BrushLocation.Y] = new TileReference<byte, byte>();
|
||||
var ch = new int2((BrushLocation.X) / ChunkSize, (BrushLocation.Y) / ChunkSize);
|
||||
if (Chunks.ContainsKey(ch))
|
||||
{
|
||||
@@ -209,7 +209,7 @@ namespace OpenRA.Editor
|
||||
for (var i = 0; i < ChunkSize; i++)
|
||||
for (var j = 0; j < ChunkSize; j++)
|
||||
{
|
||||
var tr = Map.MapTiles[u * ChunkSize + i, v * ChunkSize + j];
|
||||
var tr = Map.MapTiles.Value[u * ChunkSize + i, v * ChunkSize + j];
|
||||
var tile = TileSet.Tiles[tr.type];
|
||||
var index = (tr.index < tile.TileBitmapBytes.Count) ? tr.index : (byte)0;
|
||||
var rawImage = tile.TileBitmapBytes[index];
|
||||
@@ -217,9 +217,9 @@ namespace OpenRA.Editor
|
||||
for (var y = 0; y < TileSet.TileSize; y++)
|
||||
p[(j * TileSet.TileSize + y) * stride + i * TileSet.TileSize + x] = Palette.GetColor(rawImage[x + TileSet.TileSize * y]).ToArgb();
|
||||
|
||||
if (Map.MapResources[u * ChunkSize + i, v * ChunkSize + j].type != 0)
|
||||
if (Map.MapResources.Value[u * ChunkSize + i, v * ChunkSize + j].type != 0)
|
||||
{
|
||||
var resourceImage = ResourceTemplates[Map.MapResources[u * ChunkSize + i, v * ChunkSize + j].type].Bitmap;
|
||||
var resourceImage = ResourceTemplates[Map.MapResources.Value[u * ChunkSize + i, v * ChunkSize + j].type].Bitmap;
|
||||
var srcdata = resourceImage.LockBits(new Rectangle(0, 0, resourceImage.Width, resourceImage.Height),
|
||||
ImageLockMode.ReadOnly, PixelFormat.Format32bppArgb);
|
||||
|
||||
|
||||
Reference in New Issue
Block a user